Blog entry by Admin User
Anyone in the world
(1)求a;
(2)证明:存在直线y=b,其余两条曲线y=f(x)和y=g(x)共有三个不同的交点,且从左到右的三个交点的横坐标成等差数列。
You can input this as <code>-((2*x*cos(1/(x^2+1)))/(x^2+1)^2)</code>
[ Modified: Monday, 13 June 2022, 11:24 AM ]
(1)求a;
(2)证明:存在直线y=b,其余两条曲线y=f(x)和y=g(x)共有三个不同的交点,且从左到右的三个交点的横坐标成等差数列。
You can input this as <code>-((2*x*cos(1/(x^2+1)))/(x^2+1)^2)</code>